What are the solutions to the equation 15t^2-t-6=1,5t^2-t-6=0 ?

The solutions to the equation 15t^2-t-6=1,5t^2-t-6=0 are t=(1+sqrt(421))/(30),t=(1-sqrt(421))/(30)

Find the zeros of 15t^2-t-6=1,5t^2-t-6=0

The zeros of 15t^2-t-6=1,5t^2-t-6=0 are t=(1+sqrt(421))/(30),t=(1-sqrt(421))/(30)

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15 t^{2} - t - 6 = 1, 5 t^{2} - t - 6 = 0

t = \frac{1 + 421}{30}, t = \frac{1 - 421}{30}

Decimal Notation

t = 0.71727 \dots, t = - 0.65060 \dots

Solution steps

15 t^{2} - t - 6 = 1

Move

1

to the left side

15 t^{2} - t - 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 15 ( - 7 )}{2 \cdot 15}

(- 1)^{2} - 4 \cdot 15 (- 7) = 421

t_{1, 2} = \frac{- ( - 1 ) \pm 421}{2 \cdot 15}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 421}{2 \cdot 15}, t_{2} = \frac{- ( - 1 ) - 421}{2 \cdot 15}

t = \frac{- ( - 1 ) + 421}{2 \cdot 15} : \frac{1 + 421}{30}

t = \frac{- ( - 1 ) - 421}{2 \cdot 15} : \frac{1 - 421}{30}

The solutions to the quadratic equation are:

t = \frac{1 + 421}{30}, t = \frac{1 - 421}{30}

x^{2} - 8 x - 22 = 6

x^{2} + \frac{7}{5} x + \frac{13}{100} = 0

(x - 9) (x + 9) = 0

2 m^{2} - 3 m + 1 = 0

2 x^{2} + 19 x - 33 = 0

What are the solutions to the equation 15t^2-t-6=1,5t^2-t-6=0 ?
The solutions to the equation 15t^2-t-6=1,5t^2-t-6=0 are t=(1+sqrt(421))/(30),t=(1-sqrt(421))/(30)
Find the zeros of 15t^2-t-6=1,5t^2-t-6=0
The zeros of 15t^2-t-6=1,5t^2-t-6=0 are t=(1+sqrt(421))/(30),t=(1-sqrt(421))/(30)