What are the solutions to the equation 32=2x^2 ?

The solutions to the equation 32=2x^2 are x=4,x=-4

Find the zeros of 32=2x^2

The zeros of 32=2x^2 are x=4,x=-4

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32 = 2 x^{2}

x = 4, x = - 4

Solution steps

32 = 2 x^{2}

Switch sides

2 x^{2} = 32

Divide both sides by

2

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

f^{2} - 12 f = 0

x^{2} + 11 x = - 24

x, 6 x^{2} + 11 x - 10 = 0

2 k^{2} = - 3 k - 7

\frac{3}{4} (x + 2) = 2 x^{2} + 2 x

What are the solutions to the equation 32=2x^2 ?
The solutions to the equation 32=2x^2 are x=4,x=-4
Find the zeros of 32=2x^2
The zeros of 32=2x^2 are x=4,x=-4