What are the solutions to the equation -7n^2=-488 ?

The solutions to the equation -7n^2=-488 are n=(2sqrt(122))/(sqrt(7)),n=-(2sqrt(122))/(sqrt(7))

Find the zeros of -7n^2=-488

The zeros of -7n^2=-488 are n=(2sqrt(122))/(sqrt(7)),n=-(2sqrt(122))/(sqrt(7))

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- 7 n^{2} = - 488

n = \frac{2 122}{7}, n = - \frac{2 122}{7}

Decimal Notation

n = 8.34950 \dots, n = - 8.34950 \dots

Solution steps

- 7 n^{2} = - 488

Divide both sides by

- 7

n^{2} = \frac{488}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{488}{7}, n = - \frac{488}{7}

\frac{488}{7} = \frac{2 122}{7}

- \frac{488}{7} = - \frac{2 122}{7}

n = \frac{2 122}{7}, n = - \frac{2 122}{7}

x^{2} + 1 x - 7 = 0

x, (x - 2)^{2} = 3

3 x^{2} - x - 3

- x^{2} - 6 x - 10 = 0

(x + 1)^{2} = (x + 2)^{2} + (x + 3)^{2}

What are the solutions to the equation -7n^2=-488 ?
The solutions to the equation -7n^2=-488 are n=(2sqrt(122))/(sqrt(7)),n=-(2sqrt(122))/(sqrt(7))
Find the zeros of -7n^2=-488
The zeros of -7n^2=-488 are n=(2sqrt(122))/(sqrt(7)),n=-(2sqrt(122))/(sqrt(7))