What are the solutions to the equation 6=y^2-5y ?

The solutions to the equation 6=y^2-5y are y=6,y=-1

Find the zeros of 6=y^2-5y

The zeros of 6=y^2-5y are y=6,y=-1

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6 = y^{2} - 5 y

y = 6, y = - 1

Solution steps

6 = y^{2} - 5 y

Switch sides

y^{2} - 5 y = 6

Move

6

to the left side

y^{2} - 5 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

y_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

y = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

y = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

y = 6, y = - 1

x^{2} + 10 x + 7 = 0

25 + x^{2} = 169

(x + 1)^{2} + 3 = 0

x (x + 5) = 6

x (7 x - 6) = 0

What are the solutions to the equation 6=y^2-5y ?
The solutions to the equation 6=y^2-5y are y=6,y=-1
Find the zeros of 6=y^2-5y
The zeros of 6=y^2-5y are y=6,y=-1