What are the solutions to the equation p^2-20p+100=0 ?

The solutions to the equation p^2-20p+100=0 are p=10

Find the zeros of p^2-20p+100=0

The zeros of p^2-20p+100=0 are p=10

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p^{2} - 20 p + 100 = 0

p = 10

Solution steps

p^{2} - 20 p + 100 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 100 = 0

p_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 1}

p = \frac{- ( - 20 )}{2 \cdot 1}

\frac{- ( - 20 )}{2 \cdot 1} = 10

p = 10

The solution to the quadratic equation is:

p = 10

4 r^{2} + 8 r + 4 = 0

(6 X - 4) (3 X + 5) = (4 X - 9) (3 X + 5)

m^{2} - 6 m + 8 = 0

4 x (x + 4) = 5 (x - 9)

9 x^{2} - 5 x - 2 = - 1 - x

What are the solutions to the equation p^2-20p+100=0 ?
The solutions to the equation p^2-20p+100=0 are p=10
Find the zeros of p^2-20p+100=0
The zeros of p^2-20p+100=0 are p=10