What are the solutions to the equation b^2x^2+2bxa=3a^2 ?

The solutions to the equation b^2x^2+2bxa=3a^2 are x= a/b ,x=-(3a)/b ;\quad b\ne 0

Find the zeros of b^2x^2+2bxa=3a^2

The zeros of b^2x^2+2bxa=3a^2 are x= a/b ,x=-(3a)/b ;\quad b\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

b^{2} x^{2} + 2 b x a = 3 a^{2}

x = \frac{a}{b}, x = - \frac{3 a}{b}; b \neq = 0

Solution steps

b^{2} x^{2} + 2 b x a = 3 a^{2}

Move

3 a^{2}

to the left side

b^{2} x^{2} + 2 b x a - 3 a^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

b^{2} x^{2} + 2 ba x - 3 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 ba \pm ( 2 ba ) ^{2} - 4 b ^{2} ( - 3 a ^{2} )}{2 b ^{2}}

Simplify

(2 ba)^{2} - 4 b^{2} (- 3 a^{2}) : 4 ba

x_{1, 2} = \frac{- 2 ba \pm 4 ba}{2 b ^{2}}; b \neq = 0

Separate the solutions

x_{1} = \frac{- 2 ba + 4 ba}{2 b ^{2}}, x_{2} = \frac{- 2 ba - 4 ba}{2 b ^{2}}

x = \frac{- 2 ba + 4 ba}{2 b ^{2}} : \frac{a}{b}

x = \frac{- 2 ba - 4 ba}{2 b ^{2}} : - \frac{3 a}{b}

The solutions to the quadratic equation are:

x = \frac{a}{b}, x = - \frac{3 a}{b}; b \neq = 0

2 x (10 x + 8) = - 3 (x + 1)

- x^{2} + 8 = 0

(a - 7)^{2} = 49 + 4 a

(x - 3) (x - 5) = 1

(1.5 \cdot 1 0^{8}) x^{2} + x - 0.327 = 0, x

What are the solutions to the equation b^2x^2+2bxa=3a^2 ?
The solutions to the equation b^2x^2+2bxa=3a^2 are x= a/b ,x=-(3a)/b ;\quad b\ne 0
Find the zeros of b^2x^2+2bxa=3a^2
The zeros of b^2x^2+2bxa=3a^2 are x= a/b ,x=-(3a)/b ;\quad b\ne 0