What are the solutions to the equation x^2-18x-2=-10 ?

The solutions to the equation x^2-18x-2=-10 are x=9+sqrt(73),x=9-sqrt(73)

Find the zeros of x^2-18x-2=-10

The zeros of x^2-18x-2=-10 are x=9+sqrt(73),x=9-sqrt(73)

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x^{2} - 18 x - 2 = - 10

x = 9 + 73, x = 9 - 73

Decimal Notation

x = 17.54400 \dots, x = 0.45599 \dots

Solution steps

x^{2} - 18 x - 2 = - 10

Move

10

to the left side

x^{2} - 18 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 8 = 273

x_{1, 2} = \frac{- ( - 18 ) \pm 2 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 73}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 73}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 73}{2 \cdot 1} : 9 + 73

x = \frac{- ( - 18 ) - 2 73}{2 \cdot 1} : 9 - 73

The solutions to the quadratic equation are:

x = 9 + 73, x = 9 - 73

(10 - 5 x) (x + 5) - 6 x = 3 x (8 - 4 x)

- 16 t^{2} + 37 t - 20 = 0

x^{2} + x - 7 = 17 - x - x^{2}

p^{2} + 7 p - 8 = 0

y, x^{2} + 2 x y - 4 + y^{2} = 0

What are the solutions to the equation x^2-18x-2=-10 ?
The solutions to the equation x^2-18x-2=-10 are x=9+sqrt(73),x=9-sqrt(73)
Find the zeros of x^2-18x-2=-10
The zeros of x^2-18x-2=-10 are x=9+sqrt(73),x=9-sqrt(73)