What are the solutions to the equation (x-5)^2-7=8 ?

The solutions to the equation (x-5)^2-7=8 are x=sqrt(15)+5,x=-sqrt(15)+5

Find the zeros of (x-5)^2-7=8

The zeros of (x-5)^2-7=8 are x=sqrt(15)+5,x=-sqrt(15)+5

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(x - 5)^{2} - 7 = 8

x = 15 + 5, x = - 15 + 5

Decimal Notation

x = 8.87298 \dots, x = 1.12701 \dots

Solution steps

(x - 5)^{2} - 7 = 8

Move

7

to the right side

(x - 5)^{2} = 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 15 : x = 15 + 5

Solve

x - 5 = - 15 : x = - 15 + 5

The solutions to the quadratic equation are:

x = 15 + 5, x = - 15 + 5

y^{2} - 4 y + 12 + 4 = 0

2 x^{2} - 3 x - 1 = (x + 3) (x + 4)

- 16 x^{2} = 0

x^{2} + 3 x - 48 = 0

4 x^{2} = 1, 2 x + 9 = 0

What are the solutions to the equation (x-5)^2-7=8 ?
The solutions to the equation (x-5)^2-7=8 are x=sqrt(15)+5,x=-sqrt(15)+5
Find the zeros of (x-5)^2-7=8
The zeros of (x-5)^2-7=8 are x=sqrt(15)+5,x=-sqrt(15)+5