What are the solutions to the equation -7x^2+7x+140=0 ?

The solutions to the equation -7x^2+7x+140=0 are x=-4,x=5

Find the zeros of -7x^2+7x+140=0

The zeros of -7x^2+7x+140=0 are x=-4,x=5

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- 7 x^{2} + 7 x + 140 = 0

x = - 4, x = 5

Solution steps

- 7 x^{2} + 7 x + 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 7 ) \cdot 140}{2 ( - 7 )}

7^{2} - 4 (- 7) \cdot 140 = 63

x_{1, 2} = \frac{- 7 \pm 63}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 7 + 63}{2 ( - 7 )}, x_{2} = \frac{- 7 - 63}{2 ( - 7 )}

x = \frac{- 7 + 63}{2 ( - 7 )} : - 4

x = \frac{- 7 - 63}{2 ( - 7 )} : 5

The solutions to the quadratic equation are:

x = - 4, x = 5

x, x^{2} + y^{2} - 2 y - z + 1 = 0

x, x^{2} + 4 x + 8 = 0

(x - 4)^{2} = 8

12 x + 15 = 3 x^{2}

0.0935 x^{2} + 0.90454 x - 0.66223 = 0

What are the solutions to the equation -7x^2+7x+140=0 ?
The solutions to the equation -7x^2+7x+140=0 are x=-4,x=5
Find the zeros of -7x^2+7x+140=0
The zeros of -7x^2+7x+140=0 are x=-4,x=5