What are the solutions to the equation 10-3x-x^2=0 ?

The solutions to the equation 10-3x-x^2=0 are x=-5,x=2

Find the zeros of 10-3x-x^2=0

The zeros of 10-3x-x^2=0 are x=-5,x=2

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10 - 3 x - x^{2} = 0

x = - 5, x = 2

Solution steps

10 - 3 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 10 = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 7}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 7}{2 ( - 1 )} : - 5

x = \frac{- ( - 3 ) - 7}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 5, x = 2

2 x (5 x + 5) = 88

a^{2} + 7 = 43

4 a^{2} - a - 8 = 0

5 x^{2} + 17 x + 4 = 0

- 2 x^{2} + 7 x + 1 = 0

What are the solutions to the equation 10-3x-x^2=0 ?
The solutions to the equation 10-3x-x^2=0 are x=-5,x=2
Find the zeros of 10-3x-x^2=0
The zeros of 10-3x-x^2=0 are x=-5,x=2