What are the solutions to the equation (x+4)(x-2)=5 ?

The solutions to the equation (x+4)(x-2)=5 are x=-1+sqrt(14),x=-1-sqrt(14)

Find the zeros of (x+4)(x-2)=5

The zeros of (x+4)(x-2)=5 are x=-1+sqrt(14),x=-1-sqrt(14)

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(x + 4) (x - 2) = 5

x = - 1 + 14, x = - 1 - 14

Decimal Notation

x = 2.74165 \dots, x = - 4.74165 \dots

Solution steps

(x + 4) (x - 2) = 5

Expand

(x + 4) (x - 2) : x^{2} + 2 x - 8

x^{2} + 2 x - 8 = 5

Move

5

to the left side

x^{2} + 2 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 13) = 214

x_{1, 2} = \frac{- 2 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 14}{2 \cdot 1}

x = \frac{- 2 + 2 14}{2 \cdot 1} : - 1 + 14

x = \frac{- 2 - 2 14}{2 \cdot 1} : - 1 - 14

The solutions to the quadratic equation are:

x = - 1 + 14, x = - 1 - 14

(x + 4) (x - 2) = 6

x^{2} - 16 x + 47 = 0

x^{2} + \frac{b}{a} x + \frac{b ^{2}}{4 a ^{2}} = \frac{b ^{2}}{4 a ^{2}} - \frac{c}{a}

3 x^{2} + 36 x + 60 = 0

6 x^{2} + 60 x + 54 = 0

What are the solutions to the equation (x+4)(x-2)=5 ?
The solutions to the equation (x+4)(x-2)=5 are x=-1+sqrt(14),x=-1-sqrt(14)
Find the zeros of (x+4)(x-2)=5
The zeros of (x+4)(x-2)=5 are x=-1+sqrt(14),x=-1-sqrt(14)