What are the solutions to the equation m^2+7m-8=0 ?

The solutions to the equation m^2+7m-8=0 are m=1,m=-8

Find the zeros of m^2+7m-8=0

The zeros of m^2+7m-8=0 are m=1,m=-8

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m^{2} + 7 m - 8 = 0

m = 1, m = - 8

Solution steps

m^{2} + 7 m - 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 8) = 9

m_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 7 + 9}{2 \cdot 1}, m_{2} = \frac{- 7 - 9}{2 \cdot 1}

m = \frac{- 7 + 9}{2 \cdot 1} : 1

m = \frac{- 7 - 9}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

m = 1, m = - 8

0 = - 16 t^{2} + 85 t + 30

h^{2} - 16 h - 17 = 0

4 x - 1 = 4 x^{2}

- 1 = \frac{1}{2} (- 9.8) t^{2}

3 (1)^{2} + 2 (1) y + y^{2} = 2

What are the solutions to the equation m^2+7m-8=0 ?
The solutions to the equation m^2+7m-8=0 are m=1,m=-8
Find the zeros of m^2+7m-8=0
The zeros of m^2+7m-8=0 are m=1,m=-8