What are the solutions to the equation n^2-16n=-12 ?

The solutions to the equation n^2-16n=-12 are n=2(4+sqrt(13)),n=2(4-sqrt(13))

Find the zeros of n^2-16n=-12

The zeros of n^2-16n=-12 are n=2(4+sqrt(13)),n=2(4-sqrt(13))

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n^{2} - 16 n = - 12

n = 2 (4 + 13), n = 2 (4 - 13)

Decimal Notation

n = 15.21110 \dots, n = 0.78889 \dots

Solution steps

n^{2} - 16 n = - 12

Move

12

to the left side

n^{2} - 16 n + 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 12 = 413

n_{1, 2} = \frac{- ( - 16 ) \pm 4 13}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 16 ) + 4 13}{2 \cdot 1}, n_{2} = \frac{- ( - 16 ) - 4 13}{2 \cdot 1}

n = \frac{- ( - 16 ) + 4 13}{2 \cdot 1} : 2 (4 + 13)

n = \frac{- ( - 16 ) - 4 13}{2 \cdot 1} : 2 (4 - 13)

The solutions to the quadratic equation are:

n = 2 (4 + 13), n = 2 (4 - 13)

x (x - 11) = 0

d^{2} - 5 d

6 x = 2 x^{2}

x, x^{2} y^{2} + 4 x^{2} - 4 y^{2} = 0

7 r^{2} = 5 r + 2

What are the solutions to the equation n^2-16n=-12 ?
The solutions to the equation n^2-16n=-12 are n=2(4+sqrt(13)),n=2(4-sqrt(13))
Find the zeros of n^2-16n=-12
The zeros of n^2-16n=-12 are n=2(4+sqrt(13)),n=2(4-sqrt(13))