What are the solutions to the equation 20x^2-130x=-200 ?

The solutions to the equation 20x^2-130x=-200 are x=4,x= 5/2

Find the zeros of 20x^2-130x=-200

The zeros of 20x^2-130x=-200 are x=4,x= 5/2

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20 x^{2} - 130 x = - 200

x = 4, x = \frac{5}{2}

Decimal Notation

x = 4, x = 2.5

Solution steps

20 x^{2} - 130 x = - 200

Move

200

to the left side

20 x^{2} - 130 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 130 ) \pm ( - 130 ) ^{2} - 4 \cdot 20 \cdot 200}{2 \cdot 20}

(- 130)^{2} - 4 \cdot 20 \cdot 200 = 30

x_{1, 2} = \frac{- ( - 130 ) \pm 30}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 130 ) + 30}{2 \cdot 20}, x_{2} = \frac{- ( - 130 ) - 30}{2 \cdot 20}

x = \frac{- ( - 130 ) + 30}{2 \cdot 20} : 4

x = \frac{- ( - 130 ) - 30}{2 \cdot 20} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 4, x = \frac{5}{2}

3 x^{2} + x + 1

3 x^{2} + x - 2

- 7 x^{2} - 2 x = 1

x^{2} + \frac{x}{20} + \frac{1}{1250} = 0

13 = \frac{5 x ^{2}}{2 ( 32.2 )} - 20 + 4 (0.1 x)^{2}

What are the solutions to the equation 20x^2-130x=-200 ?
The solutions to the equation 20x^2-130x=-200 are x=4,x= 5/2
Find the zeros of 20x^2-130x=-200
The zeros of 20x^2-130x=-200 are x=4,x= 5/2