What are the solutions to the equation 1/4 x^2+4x+16=0 ?

The solutions to the equation 1/4 x^2+4x+16=0 are x=-8

Find the zeros of 1/4 x^2+4x+16=0

The zeros of 1/4 x^2+4x+16=0 are x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{4} x^{2} + 4 x + 16 = 0

x = - 8

Solution steps

\frac{1}{4} x^{2} + 4 x + 16 = 0

Multiply both sides by

4

x^{2} + 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 1}

x = \frac{- 16}{2 \cdot 1}

\frac{- 16}{2 \cdot 1} = - 8

x = - 8

The solution to the quadratic equation is:

x = - 8

6 x + 9 = 2 x^{2}

x, z = 2 x^{2} + y^{2}

- 11 = x^{2} - 36

x^{2} - 5 x - 24 = 0

3 x (x + 4) + (x + 4)^{2} = 0

What are the solutions to the equation 1/4 x^2+4x+16=0 ?
The solutions to the equation 1/4 x^2+4x+16=0 are x=-8
Find the zeros of 1/4 x^2+4x+16=0
The zeros of 1/4 x^2+4x+16=0 are x=-8