What are the solutions to the equation 4x+x^2=5 ?

The solutions to the equation 4x+x^2=5 are x=1,x=-5

Find the zeros of 4x+x^2=5

The zeros of 4x+x^2=5 are x=1,x=-5

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4 x + x^{2} = 5

x = 1, x = - 5

Solution steps

4 x + x^{2} = 5

Move

5

to the left side

4 x + x^{2} - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 6}{2 \cdot 1}

x = \frac{- 4 + 6}{2 \cdot 1} : 1

x = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

(x - 4) (x + 2) = 27

y^{2} - y - 20 = 0

- 3 x^{2} = 24 x + 48

x^{2} + 10 x + 4

x^{2} - 3 x = 9 x

What are the solutions to the equation 4x+x^2=5 ?
The solutions to the equation 4x+x^2=5 are x=1,x=-5
Find the zeros of 4x+x^2=5
The zeros of 4x+x^2=5 are x=1,x=-5