What are the solutions to the equation 40^2+50^2=c^2 ?

The solutions to the equation 40^2+50^2=c^2 are c=10sqrt(41),c=-10sqrt(41)

Find the zeros of 40^2+50^2=c^2

The zeros of 40^2+50^2=c^2 are c=10sqrt(41),c=-10sqrt(41)

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4 0^{2} + 5 0^{2} = c^{2}

c = 1041, c = - 1041

Decimal Notation

c = 64.03124 \dots, c = - 64.03124 \dots

Solution steps

4 0^{2} + 5 0^{2} = c^{2}

Switch sides

c^{2} = 4 0^{2} + 5 0^{2}

Simplify

4 0^{2} + 5 0^{2} : 4100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 4100, c = - 4100

4100 = 1041

- 4100 = - 1041

c = 1041, c = - 1041

N = \frac{t ^{2} - t}{2}

4 x^{2} - 16 x + 3 = 0

x^{2} - 2 x - 4 = 0

x^{2} + 16 x + 9 = 0

6 y^{2} + 5 y = 4

What are the solutions to the equation 40^2+50^2=c^2 ?
The solutions to the equation 40^2+50^2=c^2 are c=10sqrt(41),c=-10sqrt(41)
Find the zeros of 40^2+50^2=c^2
The zeros of 40^2+50^2=c^2 are c=10sqrt(41),c=-10sqrt(41)