What are the solutions to the equation p^2+4p+6=0 ?

The solutions to the equation p^2+4p+6=0 are p=-2+sqrt(2)i,p=-2-sqrt(2)i

Find the zeros of p^2+4p+6=0

The zeros of p^2+4p+6=0 are p=-2+sqrt(2)i,p=-2-sqrt(2)i

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p^{2} + 4 p + 6 = 0

p = - 2 + 2 i, p = - 2 - 2 i

Solution steps

p^{2} + 4 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 6 : 22 i

p_{1, 2} = \frac{- 4 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 4 + 2 2 i}{2 \cdot 1}, p_{2} = \frac{- 4 - 2 2 i}{2 \cdot 1}

p = \frac{- 4 + 2 2 i}{2 \cdot 1} : - 2 + 2 i

p = \frac{- 4 - 2 2 i}{2 \cdot 1} : - 2 - 2 i

The solutions to the quadratic equation are:

p = - 2 + 2 i, p = - 2 - 2 i

x, x^{2} + \frac{k}{m} x = 0

r, x^{2} r^{2} - 3 x r + 3 = 0

0 = 255 - 21 t - 16 t^{2}

r, r^{2} - 1 = 0

21 x^{2} - 84 x = 0

What are the solutions to the equation p^2+4p+6=0 ?
The solutions to the equation p^2+4p+6=0 are p=-2+sqrt(2)i,p=-2-sqrt(2)i
Find the zeros of p^2+4p+6=0
The zeros of p^2+4p+6=0 are p=-2+sqrt(2)i,p=-2-sqrt(2)i