What are the solutions to the equation 9b^2+18b-56=0 ?

The solutions to the equation 9b^2+18b-56=0 are b=(-3+sqrt(65))/3 ,b=-(3+sqrt(65))/3

Find the zeros of 9b^2+18b-56=0

The zeros of 9b^2+18b-56=0 are b=(-3+sqrt(65))/3 ,b=-(3+sqrt(65))/3

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9 b^{2} + 18 b - 56 = 0

b = \frac{- 3 + 65}{3}, b = - \frac{3 + 65}{3}

Decimal Notation

b = 1.68741 \dots, b = - 3.68741 \dots

Solution steps

9 b^{2} + 18 b - 56 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 ( - 56 )}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 (- 56) = 665

b_{1, 2} = \frac{- 18 \pm 6 65}{2 \cdot 9}

Separate the solutions

b_{1} = \frac{- 18 + 6 65}{2 \cdot 9}, b_{2} = \frac{- 18 - 6 65}{2 \cdot 9}

b = \frac{- 18 + 6 65}{2 \cdot 9} : \frac{- 3 + 65}{3}

b = \frac{- 18 - 6 65}{2 \cdot 9} : - \frac{3 + 65}{3}

The solutions to the quadratic equation are:

b = \frac{- 3 + 65}{3}, b = - \frac{3 + 65}{3}

3 x^{2} - \frac{3}{2} x = \frac{1}{3}

(x - 7) (x - 1) = 0

8 x^{2} = 14 x - 3

x^{2} + 9 + 8 x = 0

4 x^{2} - 45 x - 269 = 7 x^{2} - 3 x + 7

What are the solutions to the equation 9b^2+18b-56=0 ?
The solutions to the equation 9b^2+18b-56=0 are b=(-3+sqrt(65))/3 ,b=-(3+sqrt(65))/3
Find the zeros of 9b^2+18b-56=0
The zeros of 9b^2+18b-56=0 are b=(-3+sqrt(65))/3 ,b=-(3+sqrt(65))/3