What are the solutions to the equation (x-10)(x)=600 ?

The solutions to the equation (x-10)(x)=600 are x=30,x=-20

Find the zeros of (x-10)(x)=600

The zeros of (x-10)(x)=600 are x=30,x=-20

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(x - 10) (x) = 600

x = 30, x = - 20

Solution steps

(x - 10) (x) = 600

Expand

(x - 10) (x) : x^{2} - 10 x

x^{2} - 10 x = 600

Move

600

to the left side

x^{2} - 10 x - 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 600 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 600) = 50

x_{1, 2} = \frac{- ( - 10 ) \pm 50}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 50}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 50}{2 \cdot 1}

x = \frac{- ( - 10 ) + 50}{2 \cdot 1} : 30

x = \frac{- ( - 10 ) - 50}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = 30, x = - 20

3 x^{2} + 9 x + 1

10 x^{2} - 40 x - 960 = 0

x + x^{2} + 1 = 0

(3 x - 2) (4 x - 1) = 0

x, x^{2} + y^{2} - 6 x - 4 y + 13 = 0

What are the solutions to the equation (x-10)(x)=600 ?
The solutions to the equation (x-10)(x)=600 are x=30,x=-20
Find the zeros of (x-10)(x)=600
The zeros of (x-10)(x)=600 are x=30,x=-20