What are the solutions to the equation 12x^2-5=-3 ?

The solutions to the equation 12x^2-5=-3 are x= 1/(sqrt(6)),x=-1/(sqrt(6))

Find the zeros of 12x^2-5=-3

The zeros of 12x^2-5=-3 are x= 1/(sqrt(6)),x=-1/(sqrt(6))

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12 x^{2} - 5 = - 3

x = \frac{1}{6}, x = - \frac{1}{6}

Decimal Notation

x = 0.40824 \dots, x = - 0.40824 \dots

Solution steps

12 x^{2} - 5 = - 3

Move

5

to the right side

12 x^{2} = 2

Divide both sides by

12

x^{2} = \frac{1}{6}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{6}, x = - \frac{1}{6}

\frac{1}{6} = \frac{1}{6}

- \frac{1}{6} = - \frac{1}{6}

x = \frac{1}{6}, x = - \frac{1}{6}

- 3 (x + 1)^{2} + 5 = 0

(2 (\frac{2}{3}) - 1) x^{2} + 4 x + 2 = 0

x^{2} + 48 x - 1024 = 0

x^{2} - 6 x + 20

h^{2} + 5 h - 155 = 0

What are the solutions to the equation 12x^2-5=-3 ?
The solutions to the equation 12x^2-5=-3 are x= 1/(sqrt(6)),x=-1/(sqrt(6))
Find the zeros of 12x^2-5=-3
The zeros of 12x^2-5=-3 are x= 1/(sqrt(6)),x=-1/(sqrt(6))