What are the solutions to the equation 0=x^2-13x+12 ?

The solutions to the equation 0=x^2-13x+12 are x=12,x=1

Find the zeros of 0=x^2-13x+12

The zeros of 0=x^2-13x+12 are x=12,x=1

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0 = x^{2} - 13 x + 12

x = 12, x = 1

Solution steps

0 = x^{2} - 13 x + 12

Switch sides

x^{2} - 13 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 12 = 11

x_{1, 2} = \frac{- ( - 13 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 11}{2 \cdot 1}

x = \frac{- ( - 13 ) + 11}{2 \cdot 1} : 12

x = \frac{- ( - 13 ) - 11}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 12, x = 1

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4 x^{2} + 266 x - 3096 = 0

3 x^{2} + 2 x - 1 = - 2 x^{2}

What are the solutions to the equation 0=x^2-13x+12 ?
The solutions to the equation 0=x^2-13x+12 are x=12,x=1
Find the zeros of 0=x^2-13x+12
The zeros of 0=x^2-13x+12 are x=12,x=1