What are the solutions to the equation solvefor x,x^2-4x=-4 ?

The solutions to the equation solvefor x,x^2-4x=-4 are x=2

Find the zeros of solvefor x,x^2-4x=-4

The zeros of solvefor x,x^2-4x=-4 are x=2

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x, x^{2} - 4 x = - 4

x = 2

Solution steps

x^{2} - 4 x = - 4

Move

4

to the left side

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

n^{2} + 4 n = 32

12 x^{2} - 12 x - 2 = 0

x^{2} + 3 x = 108

x, f = x^{2} + y^{2} + 2 x y

6 x^{2} + 4 x + 3 = 0

What are the solutions to the equation solvefor x,x^2-4x=-4 ?
The solutions to the equation solvefor x,x^2-4x=-4 are x=2
Find the zeros of solvefor x,x^2-4x=-4
The zeros of solvefor x,x^2-4x=-4 are x=2