What are the solutions to the equation 4t^2-9t+5=0 ?

The solutions to the equation 4t^2-9t+5=0 are t= 5/4 ,t=1

Find the zeros of 4t^2-9t+5=0

The zeros of 4t^2-9t+5=0 are t= 5/4 ,t=1

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4 t^{2} - 9 t + 5 = 0

t = \frac{5}{4}, t = 1

Decimal Notation

t = 1.25, t = 1

Solution steps

4 t^{2} - 9 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 5 = 1

t_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 4}, t_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 4}

t = \frac{- ( - 9 ) + 1}{2 \cdot 4} : \frac{5}{4}

t = \frac{- ( - 9 ) - 1}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

t = \frac{5}{4}, t = 1

3 k^{2} - 18 k - 21 = 0

m^{2} - 6 m - 55 = 0

0 = 6 x^{2} - 6 x - 72

25 x^{2} - 6 x = 0

n^{2} - 13 n = - 40

What are the solutions to the equation 4t^2-9t+5=0 ?
The solutions to the equation 4t^2-9t+5=0 are t= 5/4 ,t=1
Find the zeros of 4t^2-9t+5=0
The zeros of 4t^2-9t+5=0 are t= 5/4 ,t=1