What are the solutions to the equation -x(x+3)2=-5(x+8) ?

The solutions to the equation -x(x+3)2=-5(x+8) are x=-(1+sqrt(321))/4 ,x=(sqrt(321)-1)/4

Find the zeros of -x(x+3)2=-5(x+8)

The zeros of -x(x+3)2=-5(x+8) are x=-(1+sqrt(321))/4 ,x=(sqrt(321)-1)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x (x + 3) 2 = - 5 (x + 8)

x = - \frac{1 + 321}{4}, x = \frac{321 - 1}{4}

Decimal Notation

x = - 4.72911 \dots, x = 4.22911 \dots

Solution steps

- x (x + 3) \cdot 2 = - 5 (x + 8)

Expand

- x (x + 3) \cdot 2 : - 2 x^{2} - 6 x

Expand

- 5 (x + 8) : - 5 x - 40

- 2 x^{2} - 6 x = - 5 x - 40

Move

40

to the left side

- 2 x^{2} - 6 x + 40 = - 5 x

Move

5 x

to the left side

- 2 x^{2} - x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 40}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 40 = 321

x_{1, 2} = \frac{- ( - 1 ) \pm 321}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 321}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 321}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 321}{2 ( - 2 )} : - \frac{1 + 321}{4}

x = \frac{- ( - 1 ) - 321}{2 ( - 2 )} : \frac{321 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 321}{4}, x = \frac{321 - 1}{4}

x^{2} - 10 x + 44

5 x^{2} - 2 x = 0

2 m^{2} - 3 m - 2 = 0

0 = 9 x^{2} - 25

(2 x + 10) (3 x - 1) = 150

What are the solutions to the equation -x(x+3)2=-5(x+8) ?
The solutions to the equation -x(x+3)2=-5(x+8) are x=-(1+sqrt(321))/4 ,x=(sqrt(321)-1)/4
Find the zeros of -x(x+3)2=-5(x+8)
The zeros of -x(x+3)2=-5(x+8) are x=-(1+sqrt(321))/4 ,x=(sqrt(321)-1)/4