What are the solutions to the equation m^2+10m-49=0 ?

The solutions to the equation m^2+10m-49=0 are m=-5+sqrt(74),m=-5-sqrt(74)

Find the zeros of m^2+10m-49=0

The zeros of m^2+10m-49=0 are m=-5+sqrt(74),m=-5-sqrt(74)

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m^{2} + 10 m - 49 = 0

m = - 5 + 74, m = - 5 - 74

Decimal Notation

m = 3.60232 \dots, m = - 13.60232 \dots

Solution steps

m^{2} + 10 m - 49 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 49) = 274

m_{1, 2} = \frac{- 10 \pm 2 74}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 10 + 2 74}{2 \cdot 1}, m_{2} = \frac{- 10 - 2 74}{2 \cdot 1}

m = \frac{- 10 + 2 74}{2 \cdot 1} : - 5 + 74

m = \frac{- 10 - 2 74}{2 \cdot 1} : - 5 - 74

The solutions to the quadratic equation are:

m = - 5 + 74, m = - 5 - 74

x (2 x - 7) = 0

7 x + 3 (x^{2} - 5) = x - 3

5 x^{2} - x - 5 = 0

2 x^{2} - x = 8

2 x^{2} - x = x

What are the solutions to the equation m^2+10m-49=0 ?
The solutions to the equation m^2+10m-49=0 are m=-5+sqrt(74),m=-5-sqrt(74)
Find the zeros of m^2+10m-49=0
The zeros of m^2+10m-49=0 are m=-5+sqrt(74),m=-5-sqrt(74)