What are the solutions to the equation x^2+(2+sqrt(5))x+2sqrt(5)=0 ?

The solutions to the equation x^2+(2+sqrt(5))x+2sqrt(5)=0 are x=-2,x=-sqrt(5)

Find the zeros of x^2+(2+sqrt(5))x+2sqrt(5)=0

The zeros of x^2+(2+sqrt(5))x+2sqrt(5)=0 are x=-2,x=-sqrt(5)

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x^{2} + (2 + 5) x + 25 = 0

x = - 2, x = - 5

Decimal Notation

x = - 2, x = - 2.23606 \dots

Solution steps

x^{2} + (2 + 5) x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 2 + 5 ) \pm ( 2 + 5 ) ^{2} - 4 \cdot 1 \cdot 2 5}{2 \cdot 1}

(2 + 5)^{2} - 4 \cdot 1 \cdot 25 = 5 - 2

x_{1, 2} = \frac{- ( 2 + 5 ) \pm ( 5 - 2 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( 2 + 5 ) + 5 - 2}{2 \cdot 1}, x_{2} = \frac{- ( 2 + 5 ) - ( 5 - 2 )}{2 \cdot 1}

x = \frac{- ( 2 + 5 ) + 5 - 2}{2 \cdot 1} : - 2

x = \frac{- ( 2 + 5 ) - ( 5 - 2 )}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

y^{2} = \frac{3}{4} y - \frac{1}{8}

2 x + 19 = x^{2} + 4 x + 4

m^{2} + 9 m + 18 = 0

3 z^{2} + 1 = 0

(2 x + 1)^{2} - (x + 3)^{2} = - 3

What are the solutions to the equation x^2+(2+sqrt(5))x+2sqrt(5)=0 ?
The solutions to the equation x^2+(2+sqrt(5))x+2sqrt(5)=0 are x=-2,x=-sqrt(5)
Find the zeros of x^2+(2+sqrt(5))x+2sqrt(5)=0
The zeros of x^2+(2+sqrt(5))x+2sqrt(5)=0 are x=-2,x=-sqrt(5)