What are the solutions to the equation (m-5)(m-10)=6 ?

The solutions to the equation (m-5)(m-10)=6 are m=11,m=4

Find the zeros of (m-5)(m-10)=6

The zeros of (m-5)(m-10)=6 are m=11,m=4

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(m - 5) (m - 10) = 6

m = 11, m = 4

Solution steps

(m - 5) (m - 10) = 6

Expand

(m - 5) (m - 10) : m^{2} - 15 m + 50

m^{2} - 15 m + 50 = 6

Move

6

to the left side

m^{2} - 15 m + 44 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 44 = 7

m_{1, 2} = \frac{- ( - 15 ) \pm 7}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 15 ) + 7}{2 \cdot 1}, m_{2} = \frac{- ( - 15 ) - 7}{2 \cdot 1}

m = \frac{- ( - 15 ) + 7}{2 \cdot 1} : 11

m = \frac{- ( - 15 ) - 7}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

m = 11, m = 4

4 x^{2} - 13 x + 6 = 0

- x^{2} + 4 x - 13 = 0

n^{2} - 23 n + 120 = 0

2 x^{2} + 10 - 4 = 0

- 2 x^{2} + 8 x - 18 = 0

What are the solutions to the equation (m-5)(m-10)=6 ?
The solutions to the equation (m-5)(m-10)=6 are m=11,m=4
Find the zeros of (m-5)(m-10)=6
The zeros of (m-5)(m-10)=6 are m=11,m=4