What are the solutions to the equation solvefor t,-0.8t^2+32t=0 ?

The solutions to the equation solvefor t,-0.8t^2+32t=0 are t=0,t=40

Find the zeros of solvefor t,-0.8t^2+32t=0

The zeros of solvefor t,-0.8t^2+32t=0 are t=0,t=40

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t, - 0.8 t^{2} + 32 t = 0

t = 0, t = 40

Solution steps

- 0.8 t^{2} + 32 t = 0

Multiply both sides by

10

- 8 t^{2} + 320 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 320 \pm 32 0 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

32 0^{2} - 4 (- 8) \cdot 0 = 320

t_{1, 2} = \frac{- 320 \pm 320}{2 ( - 8 )}

Separate the solutions

t_{1} = \frac{- 320 + 320}{2 ( - 8 )}, t_{2} = \frac{- 320 - 320}{2 ( - 8 )}

t = \frac{- 320 + 320}{2 ( - 8 )} : 0

t = \frac{- 320 - 320}{2 ( - 8 )} : 40

The solutions to the quadratic equation are:

t = 0, t = 40

- 4.9 x^{2} - 3 x + 30

5 x^{2} + 30 x + 45 = 0

y^{2} - 5 y = 2 y

- 3 x^{2} - 12 x - 5 = 0

20 x^{2} + 25 x = 0

What are the solutions to the equation solvefor t,-0.8t^2+32t=0 ?
The solutions to the equation solvefor t,-0.8t^2+32t=0 are t=0,t=40
Find the zeros of solvefor t,-0.8t^2+32t=0
The zeros of solvefor t,-0.8t^2+32t=0 are t=0,t=40