What are the solutions to the equation 2x^2-16x+16=-10+16 ?

The solutions to the equation 2x^2-16x+16=-10+16 are x=4+sqrt(11),x=4-sqrt(11)

Find the zeros of 2x^2-16x+16=-10+16

The zeros of 2x^2-16x+16=-10+16 are x=4+sqrt(11),x=4-sqrt(11)

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2 x^{2} - 16 x + 16 = - 10 + 16

x = 4 + 11, x = 4 - 11

Decimal

x = 7.31662 \dots, x = 0.68337 \dots

Solution steps

2 x^{2} - 16 x + 16 = - 10 + 16

Refine

2 x^{2} - 16 x + 16 = 6

Move

6

to the left side

2 x^{2} - 16 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 10 = 411

x_{1, 2} = \frac{- ( - 16 ) \pm 4 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 11}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 4 11}{2 \cdot 2}

x = \frac{- ( - 16 ) + 4 11}{2 \cdot 2} : 4 + 11

x = \frac{- ( - 16 ) - 4 11}{2 \cdot 2} : 4 - 11

The solutions to the quadratic equation are:

x = 4 + 11, x = 4 - 11

2.5 x^{2} + 25 x - 240 = 0

m^{2} - 12 m = 0

4 x^{2} - 13 x + 9 = 0

y^{1} = y^{2}

12 x^{2} - 24 x = 0

What are the solutions to the equation 2x^2-16x+16=-10+16 ?
The solutions to the equation 2x^2-16x+16=-10+16 are x=4+sqrt(11),x=4-sqrt(11)
Find the zeros of 2x^2-16x+16=-10+16
The zeros of 2x^2-16x+16=-10+16 are x=4+sqrt(11),x=4-sqrt(11)