What are the solutions to the equation -2x^2+12x-5=0 ?

The solutions to the equation -2x^2+12x-5=0 are x=(6-sqrt(26))/2 ,x=(6+sqrt(26))/2

Find the zeros of -2x^2+12x-5=0

The zeros of -2x^2+12x-5=0 are x=(6-sqrt(26))/2 ,x=(6+sqrt(26))/2

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- 2 x^{2} + 12 x - 5 = 0

x = \frac{6 - 26}{2}, x = \frac{6 + 26}{2}

Decimal Notation

x = 0.45049 \dots, x = 5.54950 \dots

Solution steps

- 2 x^{2} + 12 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 5) = 226

x_{1, 2} = \frac{- 12 \pm 2 26}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 26}{2 ( - 2 )}, x_{2} = \frac{- 12 - 2 26}{2 ( - 2 )}

x = \frac{- 12 + 2 26}{2 ( - 2 )} : \frac{6 - 26}{2}

x = \frac{- 12 - 2 26}{2 ( - 2 )} : \frac{6 + 26}{2}

The solutions to the quadratic equation are:

x = \frac{6 - 26}{2}, x = \frac{6 + 26}{2}

x^{2} - \frac{3}{2} x = \frac{7}{16}

1 4^{2} + x^{2} = 5 0^{2}

x^{2} + 5 x + 5 = 0

x^{2} + 64 = 100

5 m^{2} - 8 m + 3 = 0

What are the solutions to the equation -2x^2+12x-5=0 ?
The solutions to the equation -2x^2+12x-5=0 are x=(6-sqrt(26))/2 ,x=(6+sqrt(26))/2
Find the zeros of -2x^2+12x-5=0
The zeros of -2x^2+12x-5=0 are x=(6-sqrt(26))/2 ,x=(6+sqrt(26))/2