What are the solutions to the equation 7x^2-4x+8=0 ?

The solutions to the equation 7x^2-4x+8=0 are x= 2/7+i(2sqrt(13))/7 ,x= 2/7-i(2sqrt(13))/7

Find the zeros of 7x^2-4x+8=0

The zeros of 7x^2-4x+8=0 are x= 2/7+i(2sqrt(13))/7 ,x= 2/7-i(2sqrt(13))/7

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7 x^{2} - 4 x + 8 = 0

x = \frac{2}{7} + i \frac{2 13}{7}, x = \frac{2}{7} - i \frac{2 13}{7}

Solution steps

7 x^{2} - 4 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 7 \cdot 8}{2 \cdot 7}

Simplify

(- 4)^{2} - 4 \cdot 7 \cdot 8 : 413 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 13 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 13 i}{2 \cdot 7}, x_{2} = \frac{- ( - 4 ) - 4 13 i}{2 \cdot 7}

x = \frac{- ( - 4 ) + 4 13 i}{2 \cdot 7} : \frac{2}{7} + i \frac{2 13}{7}

x = \frac{- ( - 4 ) - 4 13 i}{2 \cdot 7} : \frac{2}{7} - i \frac{2 13}{7}

The solutions to the quadratic equation are:

x = \frac{2}{7} + i \frac{2 13}{7}, x = \frac{2}{7} - i \frac{2 13}{7}

3 x^{2} - 80 x + 400 = 0

v^{2} - 40 = 0

x (4 x - 3) = 45

9 - 2 (x - 3)^{2} = 2 - x

2 - (2 x^{2} + 2 x) = - 10

What are the solutions to the equation 7x^2-4x+8=0 ?
The solutions to the equation 7x^2-4x+8=0 are x= 2/7+i(2sqrt(13))/7 ,x= 2/7-i(2sqrt(13))/7
Find the zeros of 7x^2-4x+8=0
The zeros of 7x^2-4x+8=0 are x= 2/7+i(2sqrt(13))/7 ,x= 2/7-i(2sqrt(13))/7