What are the solutions to the equation -2x^2+7x-4=0 ?

The solutions to the equation -2x^2+7x-4=0 are x=(7-sqrt(17))/4 ,x=(7+sqrt(17))/4

Find the zeros of -2x^2+7x-4=0

The zeros of -2x^2+7x-4=0 are x=(7-sqrt(17))/4 ,x=(7+sqrt(17))/4

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- 2 x^{2} + 7 x - 4 = 0

x = \frac{7 - 17}{4}, x = \frac{7 + 17}{4}

Decimal Notation

x = 0.71922 \dots, x = 2.78077 \dots

Solution steps

- 2 x^{2} + 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

7^{2} - 4 (- 2) (- 4) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 ( - 2 )}, x_{2} = \frac{- 7 - 17}{2 ( - 2 )}

x = \frac{- 7 + 17}{2 ( - 2 )} : \frac{7 - 17}{4}

x = \frac{- 7 - 17}{2 ( - 2 )} : \frac{7 + 17}{4}

The solutions to the quadratic equation are:

x = \frac{7 - 17}{4}, x = \frac{7 + 17}{4}

2 - 3 x - 4 x^{2} = 0

x^{2} + \frac{3}{3} x + \frac{7}{3} = 0

- 2 x^{2} - 17 x - 53 = 0

x, 3 y^{2} - 12 z^{2} - 4 x^{2} = 12

25 x^{2} - 20 x + 9 = 0

What are the solutions to the equation -2x^2+7x-4=0 ?
The solutions to the equation -2x^2+7x-4=0 are x=(7-sqrt(17))/4 ,x=(7+sqrt(17))/4
Find the zeros of -2x^2+7x-4=0
The zeros of -2x^2+7x-4=0 are x=(7-sqrt(17))/4 ,x=(7+sqrt(17))/4