What are the solutions to the equation x^2+4/5 x=-1/5 ?

The solutions to the equation x^2+4/5 x=-1/5 are x=-2/5+i 1/5 ,x=-2/5-i 1/5

Find the zeros of x^2+4/5 x=-1/5

The zeros of x^2+4/5 x=-1/5 are x=-2/5+i 1/5 ,x=-2/5-i 1/5

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x^{2} + \frac{4}{5} x = - \frac{1}{5}

x = - \frac{2}{5} + i \frac{1}{5}, x = - \frac{2}{5} - i \frac{1}{5}

Solution steps

x^{2} + \frac{4}{5} x = - \frac{1}{5}

Multiply both sides by

5

5 x^{2} + 4 x = - 1

Move

1

to the left side

5 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 1 : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 \cdot 5}, x_{2} = \frac{- 4 - 2 i}{2 \cdot 5}

x = \frac{- 4 + 2 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{1}{5}

x = \frac{- 4 - 2 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{1}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} + i \frac{1}{5}, x = - \frac{2}{5} - i \frac{1}{5}

16 x^{2} - 256 = 0

0.003 x^{2} - 0.04 x + 2 - a = 0

4.9 t^{2} - 20 t + 15 = 0

21 - 8 k - 2 k^{2} = 2 k^{2}

x^{2} + 12 x + 20 = 0

What are the solutions to the equation x^2+4/5 x=-1/5 ?
The solutions to the equation x^2+4/5 x=-1/5 are x=-2/5+i 1/5 ,x=-2/5-i 1/5
Find the zeros of x^2+4/5 x=-1/5
The zeros of x^2+4/5 x=-1/5 are x=-2/5+i 1/5 ,x=-2/5-i 1/5