What are the solutions to the equation 6x^2-40=x ?

The solutions to the equation 6x^2-40=x are x= 8/3 ,x=-5/2

Find the zeros of 6x^2-40=x

The zeros of 6x^2-40=x are x= 8/3 ,x=-5/2

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6 x^{2} - 40 = x

x = \frac{8}{3}, x = - \frac{5}{2}

Decimal Notation

x = 2.66666 \dots, x = - 2.5

Solution steps

6 x^{2} - 40 = x

Move

x

to the left side

6 x^{2} - 40 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 40 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 40) = 31

x_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 6}

x = \frac{- ( - 1 ) + 31}{2 \cdot 6} : \frac{8}{3}

x = \frac{- ( - 1 ) - 31}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - \frac{5}{2}

12 - b - b^{2} = 0

x (x + 1) = 110

m^{2} - 8 m + 7 = 0

(x + 3) (x + 6) = 0

3 (k^{2} - 36) + k^{2} = 6 k

What are the solutions to the equation 6x^2-40=x ?
The solutions to the equation 6x^2-40=x are x= 8/3 ,x=-5/2
Find the zeros of 6x^2-40=x
The zeros of 6x^2-40=x are x= 8/3 ,x=-5/2