What are the solutions to the equation 5x^2-9=11x ?

The solutions to the equation 5x^2-9=11x are x=(11+sqrt(301))/(10),x=(11-sqrt(301))/(10)

Find the zeros of 5x^2-9=11x

The zeros of 5x^2-9=11x are x=(11+sqrt(301))/(10),x=(11-sqrt(301))/(10)

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5 x^{2} - 9 = 11 x

x = \frac{11 + 301}{10}, x = \frac{11 - 301}{10}

Decimal Notation

x = 2.83493 \dots, x = - 0.63493 \dots

Solution steps

5 x^{2} - 9 = 11 x

Move

11 x

to the left side

5 x^{2} - 9 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 11 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 9) = 301

x_{1, 2} = \frac{- ( - 11 ) \pm 301}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 301}{2 \cdot 5}, x_{2} = \frac{- ( - 11 ) - 301}{2 \cdot 5}

x = \frac{- ( - 11 ) + 301}{2 \cdot 5} : \frac{11 + 301}{10}

x = \frac{- ( - 11 ) - 301}{2 \cdot 5} : \frac{11 - 301}{10}

The solutions to the quadratic equation are:

x = \frac{11 + 301}{10}, x = \frac{11 - 301}{10}

x, 3 x^{2} + 2 x + 2 = k x + k

x (13 - 4 x) = 0

x^{2} - 16 x + 82 = 0

2 (2 - 3 x^{2}) = 0

k^{2} - 4 k - 12 = 0

What are the solutions to the equation 5x^2-9=11x ?
The solutions to the equation 5x^2-9=11x are x=(11+sqrt(301))/(10),x=(11-sqrt(301))/(10)
Find the zeros of 5x^2-9=11x
The zeros of 5x^2-9=11x are x=(11+sqrt(301))/(10),x=(11-sqrt(301))/(10)