What are the solutions to the equation x^2+(-x)^2=1 ?

The solutions to the equation x^2+(-x)^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of x^2+(-x)^2=1

The zeros of x^2+(-x)^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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x^{2} + (- x)^{2} = 1

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

x^{2} + (- x)^{2} = 1

Expand

x^{2} + (- x)^{2} : 2 x^{2}

2 x^{2} = 1

Move

1

to the left side

2 x^{2} - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

0^{2} - 4 \cdot 2 (- 1) = 22

x_{1, 2} = \frac{- 0 \pm 2 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 2 2}{2 \cdot 2}, x_{2} = \frac{- 0 - 2 2}{2 \cdot 2}

x = \frac{- 0 + 2 2}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 0 - 2 2}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{2}

2 (x - 3)^{2} = 0

A, C^{2} + 2 XB = A XB - A^{2}

3 x^{2} - 12 x + 28

\frac{1}{2} x^{2} - 50 = 0

n^{2} + 4 n - 5 = 0

What are the solutions to the equation x^2+(-x)^2=1 ?
The solutions to the equation x^2+(-x)^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of x^2+(-x)^2=1
The zeros of x^2+(-x)^2=1 are x= 1/(sqrt(2)),x=-1/(sqrt(2))