What are the solutions to the equation x^2-64x=-3x^2+16x ?

The solutions to the equation x^2-64x=-3x^2+16x are x=20,x=0

Find the zeros of x^2-64x=-3x^2+16x

The zeros of x^2-64x=-3x^2+16x are x=20,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 64 x = - 3 x^{2} + 16 x

x = 20, x = 0

Solution steps

x^{2} - 64 x = - 3 x^{2} + 16 x

Move

16 x

to the left side

x^{2} - 80 x = - 3 x^{2}

Move

3 x^{2}

to the left side

4 x^{2} - 80 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 80)^{2} - 4 \cdot 4 \cdot 0 = 80

x_{1, 2} = \frac{- ( - 80 ) \pm 80}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 80}{2 \cdot 4}, x_{2} = \frac{- ( - 80 ) - 80}{2 \cdot 4}

x = \frac{- ( - 80 ) + 80}{2 \cdot 4} : 20

x = \frac{- ( - 80 ) - 80}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 20, x = 0

x^{2} - 19 x + 9 = 0

4 x^{2} + 3 = 103

56.5 \cdot 1000 = 1000 (9.8) (3.65) + 1000 \cdot \frac{V ^{2}}{2}

x^{2} + 15 x + 60 = 0

a^{2} - 18 a + 81 = 0

What are the solutions to the equation x^2-64x=-3x^2+16x ?
The solutions to the equation x^2-64x=-3x^2+16x are x=20,x=0
Find the zeros of x^2-64x=-3x^2+16x
The zeros of x^2-64x=-3x^2+16x are x=20,x=0