What are the solutions to the equation 3b^2-12b=15 ?

The solutions to the equation 3b^2-12b=15 are b=5,b=-1

Find the zeros of 3b^2-12b=15

The zeros of 3b^2-12b=15 are b=5,b=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 b^{2} - 12 b = 15

b = 5, b = - 1

Solution steps

3 b^{2} - 12 b = 15

Move

15

to the left side

3 b^{2} - 12 b - 15 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 15) = 18

b_{1, 2} = \frac{- ( - 12 ) \pm 18}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- ( - 12 ) + 18}{2 \cdot 3}, b_{2} = \frac{- ( - 12 ) - 18}{2 \cdot 3}

b = \frac{- ( - 12 ) + 18}{2 \cdot 3} : 5

b = \frac{- ( - 12 ) - 18}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

b = 5, b = - 1

x^{2} + 3 x - 74 = 0

x (5 x + 14) = 3

6 x^{2} + 7 x - 4 = 0

x^{2} + 12 x + 11

a^{2} + a = 2

What are the solutions to the equation 3b^2-12b=15 ?
The solutions to the equation 3b^2-12b=15 are b=5,b=-1
Find the zeros of 3b^2-12b=15
The zeros of 3b^2-12b=15 are b=5,b=-1