What are the solutions to the equation 2x^2+16x+26=0 ?

The solutions to the equation 2x^2+16x+26=0 are x=-4+sqrt(3),x=-4-sqrt(3)

Find the zeros of 2x^2+16x+26=0

The zeros of 2x^2+16x+26=0 are x=-4+sqrt(3),x=-4-sqrt(3)

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2 x^{2} + 16 x + 26 = 0

x = - 4 + 3, x = - 4 - 3

Decimal Notation

x = - 2.26794 \dots, x = - 5.73205 \dots

Solution steps

2 x^{2} + 16 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 \cdot 26}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 \cdot 26 = 43

x_{1, 2} = \frac{- 16 \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 16 + 4 3}{2 \cdot 2}, x_{2} = \frac{- 16 - 4 3}{2 \cdot 2}

x = \frac{- 16 + 4 3}{2 \cdot 2} : - 4 + 3

x = \frac{- 16 - 4 3}{2 \cdot 2} : - 4 - 3

The solutions to the quadratic equation are:

x = - 4 + 3, x = - 4 - 3

6 0^{2} + 8 0^{2} = x^{2}

x^{2} + 24 x + 150 = 0

49 x^{2} - 16 = 20

42 x^{2} = - 287 x + 392

3 x^{2} = x - 9

What are the solutions to the equation 2x^2+16x+26=0 ?
The solutions to the equation 2x^2+16x+26=0 are x=-4+sqrt(3),x=-4-sqrt(3)
Find the zeros of 2x^2+16x+26=0
The zeros of 2x^2+16x+26=0 are x=-4+sqrt(3),x=-4-sqrt(3)