What are the solutions to the equation (4x-3)^2=14 ?

The solutions to the equation (4x-3)^2=14 are x=(sqrt(14)+3)/4 ,x=(-sqrt(14)+3)/4

Find the zeros of (4x-3)^2=14

The zeros of (4x-3)^2=14 are x=(sqrt(14)+3)/4 ,x=(-sqrt(14)+3)/4

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(4 x - 3)^{2} = 14

x = \frac{14 + 3}{4}, x = \frac{- 14 + 3}{4}

Decimal Notation

x = 1.68541 \dots, x = - 0.18541 \dots

Solution steps

(4 x - 3)^{2} = 14

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 3 = 14 : x = \frac{14 + 3}{4}

Solve

4 x - 3 = - 14 : x = \frac{- 14 + 3}{4}

The solutions to the quadratic equation are:

x = \frac{14 + 3}{4}, x = \frac{- 14 + 3}{4}

∣ x - 5 ∣ + 1 \leq 2 x

x^{2} - 10 x + 16 < 0

5.4 x + 12 = 2 (2.7 x - 9)

2 x^{2} - 9 x + 6 = 0

(2 - 4)^{2}

What are the solutions to the equation (4x-3)^2=14 ?
The solutions to the equation (4x-3)^2=14 are x=(sqrt(14)+3)/4 ,x=(-sqrt(14)+3)/4
Find the zeros of (4x-3)^2=14
The zeros of (4x-3)^2=14 are x=(sqrt(14)+3)/4 ,x=(-sqrt(14)+3)/4