What are the solutions to the equation 0=12x^2-12x-24 ?

The solutions to the equation 0=12x^2-12x-24 are x=2,x=-1

Find the zeros of 0=12x^2-12x-24

The zeros of 0=12x^2-12x-24 are x=2,x=-1

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0 = 12 x^{2} - 12 x - 24

x = 2, x = - 1

Solution steps

0 = 12 x^{2} - 12 x - 24

Switch sides

12 x^{2} - 12 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 12 ( - 24 )}{2 \cdot 12}

(- 12)^{2} - 4 \cdot 12 (- 24) = 36

x_{1, 2} = \frac{- ( - 12 ) \pm 36}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 36}{2 \cdot 12}, x_{2} = \frac{- ( - 12 ) - 36}{2 \cdot 12}

x = \frac{- ( - 12 ) + 36}{2 \cdot 12} : 2

x = \frac{- ( - 12 ) - 36}{2 \cdot 12} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

(2 x + 1)^{2} - (x - 3)^{2} = 0

3 x^{2} = 30000

5 x^{2} - 17 x + 11 = 0

x^{2} - 1 = 2 x - 1

x, - 5 x (8 x - 7) = 0

What are the solutions to the equation 0=12x^2-12x-24 ?
The solutions to the equation 0=12x^2-12x-24 are x=2,x=-1
Find the zeros of 0=12x^2-12x-24
The zeros of 0=12x^2-12x-24 are x=2,x=-1