What are the solutions to the equation 3x^2+9x-3=0 ?

The solutions to the equation 3x^2+9x-3=0 are x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2

Find the zeros of 3x^2+9x-3=0

The zeros of 3x^2+9x-3=0 are x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2

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3 x^{2} + 9 x - 3 = 0

x = \frac{- 3 + 13}{2}, x = - \frac{3 + 13}{2}

Decimal Notation

x = 0.30277 \dots, x = - 3.30277 \dots

Solution steps

3 x^{2} + 9 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 3) = 313

x_{1, 2} = \frac{- 9 \pm 3 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 3 13}{2 \cdot 3}, x_{2} = \frac{- 9 - 3 13}{2 \cdot 3}

x = \frac{- 9 + 3 13}{2 \cdot 3} : \frac{- 3 + 13}{2}

x = \frac{- 9 - 3 13}{2 \cdot 3} : - \frac{3 + 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 13}{2}, x = - \frac{3 + 13}{2}

k + k + 1 = \frac{( k + 1 ) ( k + 2 )}{2}

x^{2} - x = - 12

h^{2} - h = 0

x^{2} + 81 = 18 x

6 x^{2} - 4 = 2 x^{2} + 8

What are the solutions to the equation 3x^2+9x-3=0 ?
The solutions to the equation 3x^2+9x-3=0 are x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2
Find the zeros of 3x^2+9x-3=0
The zeros of 3x^2+9x-3=0 are x=(-3+sqrt(13))/2 ,x=-(3+sqrt(13))/2