What are the solutions to the equation solvefor r,r^2-2r+2=0 ?

The solutions to the equation solvefor r,r^2-2r+2=0 are r=1+i,r=1-i

Find the zeros of solvefor r,r^2-2r+2=0

The zeros of solvefor r,r^2-2r+2=0 are r=1+i,r=1-i

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r, r^{2} - 2 r + 2 = 0

r = 1 + i, r = 1 - i

Solution steps

r^{2} - 2 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

r_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, r_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

r = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

r = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

r = 1 + i, r = 1 - i

x = \frac{1}{2} (0.004) (5 - 5000 x - 0.3)^{2}

x, x^{2} y^{2} - 16 x y^{2} + 64 y^{2} = x^{2} + 2 x - 15

0 = 12 x^{2} - 84 x + 104

0 = 43 - 4 t - 5 t^{2}

x, 5 x^{2} - 2 x y - 6 x - 25 y - 19 = 0

What are the solutions to the equation solvefor r,r^2-2r+2=0 ?
The solutions to the equation solvefor r,r^2-2r+2=0 are r=1+i,r=1-i
Find the zeros of solvefor r,r^2-2r+2=0
The zeros of solvefor r,r^2-2r+2=0 are r=1+i,r=1-i