What are the solutions to the equation (2y+3)(y-9)=0 ?

The solutions to the equation (2y+3)(y-9)=0 are y=-3/2 ,y=9

Find the zeros of (2y+3)(y-9)=0

The zeros of (2y+3)(y-9)=0 are y=-3/2 ,y=9

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(2 y + 3) (y - 9) = 0

y = - \frac{3}{2}, y = 9

Decimal Notation

y = - 1.5, y = 9

Solution steps

(2 y + 3) (y - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 y + 3 = 0 or y - 9 = 0

Solve

2 y + 3 = 0 : y = - \frac{3}{2}

Solve

y - 9 = 0 : y = 9

The solutions to the quadratic equation are:

y = - \frac{3}{2}, y = 9

y, (1 + \frac{x}{2})^{2} + 3^{2} = y^{2}

- 4.9 x^{2} + 30 x + 200 = 0

(x^{2} - 2 x - 2) = 0

x^{2} - 3 x = x - 1

3 x (2 x - 5) = 0

What are the solutions to the equation (2y+3)(y-9)=0 ?
The solutions to the equation (2y+3)(y-9)=0 are y=-3/2 ,y=9
Find the zeros of (2y+3)(y-9)=0
The zeros of (2y+3)(y-9)=0 are y=-3/2 ,y=9