What are the solutions to the equation 27(x-4)^2=3 ?

The solutions to the equation 27(x-4)^2=3 are x= 13/3 ,x= 11/3

Find the zeros of 27(x-4)^2=3

The zeros of 27(x-4)^2=3 are x= 13/3 ,x= 11/3

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27 (x - 4)^{2} = 3

x = \frac{13}{3}, x = \frac{11}{3}

Decimal Notation

x = 4.33333 \dots, x = 3.66666 \dots

Solution steps

27 (x - 4)^{2} = 3

Divide both sides by

27

(x - 4)^{2} = \frac{1}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = \frac{1}{9} : x = \frac{13}{3}

Solve

x - 4 = - \frac{1}{9} : x = \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{13}{3}, x = \frac{11}{3}

3 x^{2} + 15 = - 12

11 x (\frac{2 ( - 2 x + 11 )}{5}) = 66

8 x^{2} + 7 x + 6 = 37

5 x^{2} - 5 x - 210 = 0

12000 = 2 \cdot x^{2} 2 \cdot (\frac{24}{25})

What are the solutions to the equation 27(x-4)^2=3 ?
The solutions to the equation 27(x-4)^2=3 are x= 13/3 ,x= 11/3
Find the zeros of 27(x-4)^2=3
The zeros of 27(x-4)^2=3 are x= 13/3 ,x= 11/3