What are the solutions to the equation x^2-10ax+9a^2=0 ?

The solutions to the equation x^2-10ax+9a^2=0 are x=9a,x=a

Find the zeros of x^2-10ax+9a^2=0

The zeros of x^2-10ax+9a^2=0 are x=9a,x=a

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x^{2} - 10 a x + 9 a^{2} = 0

x = 9 a, x = a

Solution steps

x^{2} - 10 a x + 9 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 a ) \pm ( - 10 a ) ^{2} - 4 \cdot 1 \cdot 9 a ^{2}}{2 \cdot 1}

Simplify

(- 10 a)^{2} - 4 \cdot 1 \cdot 9 a^{2} : 8 a

x_{1, 2} = \frac{- ( - 10 a ) \pm 8 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 a ) + 8 a}{2 \cdot 1}, x_{2} = \frac{- ( - 10 a ) - 8 a}{2 \cdot 1}

x = \frac{- ( - 10 a ) + 8 a}{2 \cdot 1} : 9 a

x = \frac{- ( - 10 a ) - 8 a}{2 \cdot 1} : a

The solutions to the quadratic equation are:

x = 9 a, x = a

p^{2} + 11 p + 28 = 0

3 x (x - 2) - 2 (x - 1) (x + 3) = 0

lo g_{b} (7) x^{2} - lo g_{b} (49) = 0

2 x^{2} = 5 x - 3

5 x^{2} + 7 x - 10 = 0

What are the solutions to the equation x^2-10ax+9a^2=0 ?
The solutions to the equation x^2-10ax+9a^2=0 are x=9a,x=a
Find the zeros of x^2-10ax+9a^2=0
The zeros of x^2-10ax+9a^2=0 are x=9a,x=a