What are the solutions to the equation (3x-1)^2=7 ?

The solutions to the equation (3x-1)^2=7 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3

Find the zeros of (3x-1)^2=7

The zeros of (3x-1)^2=7 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3

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(3 x - 1)^{2} = 7

x = \frac{7 + 1}{3}, x = \frac{- 7 + 1}{3}

Decimal

x = 1.21525 \dots, x = - 0.54858 \dots

Solution steps

(3 x - 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 1 = 7 : x = \frac{7 + 1}{3}

Solve

3 x - 1 = - 7 : x = \frac{- 7 + 1}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 1}{3}, x = \frac{- 7 + 1}{3}

x, x^{2} + 2 x y + y^{2} + x = 0

3 x^{2} - 1 = 6 x

5 x^{2} + 9 x = 10

a, a^{2} + 6 ab = 16 b^{2}

\frac{3 - x}{1000} = \frac{40 \cdot 10}{2 \cdot 1} (3 - x - 0.7)^{2}

What are the solutions to the equation (3x-1)^2=7 ?
The solutions to the equation (3x-1)^2=7 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3
Find the zeros of (3x-1)^2=7
The zeros of (3x-1)^2=7 are x=(sqrt(7)+1)/3 ,x=(-sqrt(7)+1)/3