What are the solutions to the equation a^2+7a+2=0 ?

The solutions to the equation a^2+7a+2=0 are a=(-7+sqrt(41))/2 ,a=(-7-sqrt(41))/2

Find the zeros of a^2+7a+2=0

The zeros of a^2+7a+2=0 are a=(-7+sqrt(41))/2 ,a=(-7-sqrt(41))/2

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a^{2} + 7 a + 2 = 0

a = \frac{- 7 + 41}{2}, a = \frac{- 7 - 41}{2}

Decimal Notation

a = - 0.29843 \dots, a = - 6.70156 \dots

Solution steps

a^{2} + 7 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 2 = 41

a_{1, 2} = \frac{- 7 \pm 41}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 7 + 41}{2 \cdot 1}, a_{2} = \frac{- 7 - 41}{2 \cdot 1}

a = \frac{- 7 + 41}{2 \cdot 1} : \frac{- 7 + 41}{2}

a = \frac{- 7 - 41}{2 \cdot 1} : \frac{- 7 - 41}{2}

The solutions to the quadratic equation are:

a = \frac{- 7 + 41}{2}, a = \frac{- 7 - 41}{2}

\frac{2}{3} x^{2} + \frac{1}{4} x = 0

0 = - 16 t^{2} + 64 t + 336

\frac{1}{2} x + \frac{1}{2} = x^{2} - 1

5 x^{2} + 16 x + 12 = 0

4 x^{2} + 19 + 12 = 0

What are the solutions to the equation a^2+7a+2=0 ?
The solutions to the equation a^2+7a+2=0 are a=(-7+sqrt(41))/2 ,a=(-7-sqrt(41))/2
Find the zeros of a^2+7a+2=0
The zeros of a^2+7a+2=0 are a=(-7+sqrt(41))/2 ,a=(-7-sqrt(41))/2