What are the solutions to the equation 2(x-16)=(x-8)(x+2) ?

The solutions to the equation 2(x-16)=(x-8)(x+2) are x=4

Find the zeros of 2(x-16)=(x-8)(x+2)

The zeros of 2(x-16)=(x-8)(x+2) are x=4

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2 (x - 16) = (x - 8) (x + 2)

x = 4

Solution steps

2 (x - 16) = (x - 8) (x + 2)

Expand

2 (x - 16) : 2 x - 32

Expand

(x - 8) (x + 2) : x^{2} - 6 x - 16

2 x - 32 = x^{2} - 6 x - 16

Switch sides

x^{2} - 6 x - 16 = 2 x - 32

Move

32

to the left side

x^{2} - 6 x + 16 = 2 x

Move

2 x

to the left side

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

5 x^{2} - 2 x - 8 = 0

\frac{x ( x - 3 )}{2} = 54

0 = 1 + 5.08 t - 4.9 t^{2}

g (n) = - 2 (3 n - 1) (2 n + 1)

x + \frac{x ^{2}}{100} - n = 0

What are the solutions to the equation 2(x-16)=(x-8)(x+2) ?
The solutions to the equation 2(x-16)=(x-8)(x+2) are x=4
Find the zeros of 2(x-16)=(x-8)(x+2)
The zeros of 2(x-16)=(x-8)(x+2) are x=4